-1/(2x-4)-(x^2-4x+3)/(x-2)=0

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Solution for -1/(2x-4)-(x^2-4x+3)/(x-2)=0 equation: 



-1/(2x-4)-(x^2-4x+3)/(x-2)=0



Domain of the equation: (2x-4)!=0

We move all terms containing x to the left, all other terms to the right

2x!=4

x!=4/2

x!=2

x∈R





Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R



We calculate fractions


(-1*(x-2))/((2x-4)*(x-2))+(-(x^2-4x+3)*(2x-4))/((2x-4)*(x-2))=0



We calculate terms in parentheses: +(-1*(x-2))/((2x-4)*(x-2)), so:

-1*(x-2))/((2x-4)*(x-2)

We multiply all the terms by the denominator


-1*(x-2))

Back to the equation:

+(-1*(x-2)))





We calculate terms in parentheses: +(-(x^2-4x+3)*(2x-4))/((2x-4)*(x-2)), so:

-(x^2-4x+3)*(2x-4))/((2x-4)*(x-2)

We multiply all the terms by the denominator


-(x^2-4x+3)*(2x-4))

Back to the equation:

+(-(x^2-4x+3)*(2x-4)))

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